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Linkbreakers MCP server

Which servers in the official MCP registry are Linkbreakers's own, whether they answer, and what they offer. A program checked each of these, nobody copied them from a product page.

read 2026-10-15

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Whose server it is
  • Registry namecom.linkbreakers/docs-mcpverified in the MCP registry

The registry name sits under linkbreakers.com. The registry only lets a publisher use that namespace after proving control of the domain through DNS or HTTP.

When we asked itchecked 2026-10-15
  • Stateanswerschecked 2026-10-15
  • Tools3
  • Server calls itselfcom.linkbreakers/docs-mcp
  • Server version1.0.0
  • Protocol version2025-06-18

On 2026-10-15 the server answered initialize and tools/list without a sign-in. First answer in 58 ms.

Tools it offers3 tools · read 2026-10-15
  • search_docs

    Search the Linkbreakers help center, guides, integrations and product news, or the public QR code design templates. Returns ranked results with their URL, Markdown URL and a snippet; read a help article in full with get_article.

  • get_article

    Return the full Markdown of a Linkbreakers help center article by slug (the last segment of https://linkbreakers.com/help/article/<slug>).

  • get_pricing

    Return the current Linkbreakers plans with prices in USD per month, plan limits, signup links, how to reach sales for Enterprise, and the features included in every plan with the help article that explains each.

How to connect

Add the server to your MCP client config. Claude Desktop, Cursor and most other clients read this shape:

{
  "mcpServers": {
    "docs-mcp": {
      "type": "http",
      "url": "https://linkbreakers.com/mcp"
    }
  }
}
Other servers listed as Linkbreakers's
  • com.linkbreakers/mcpanswers, requires sign-inverified in the MCP registry

OpenAPI spec

119 paths, read 2026-10-15. Open the spec ↗

Each line is something a program found when it went looking: the registry entry, the server's own answer, a spec that parses. A missing line means we did not find it, not that it does not exist.